$R=4 H$ $\frac{\mathrm{U}^{2} \times 2 \sin \theta \cos \theta}{\mathrm{g}}=4 \times \frac{\mathrm{U}^{2} \sin ^{2} \theta}{2 \mathrm{g}}$ $\tan \th

$R=4 H$ $\frac{\mathrm{U}^{2} \times 2 \sin \theta \cos \theta}{\mathrm{g}}=4 \times \frac{\mathrm{U}^{2} \sin ^{2} \theta}{2 \mathrm{g}}$ $\tan \theta=1 \quad\left[\theta=45^{\circ}\right]$

English

3-2.Motion in PlaneMedium

The horizontal range is four times the maximum height attained by a projectile. The angle of projection is .......... $^o$

A
$90$
B
$60$
C
$45$
D
$30$

Std 11
Physics

Column $-I$

Angle of projection
Column $-II$

$A.$ $\theta \, = \,{45^o}$ $1.$ $\frac{{{K_h}}}{{{K_i}}} = \frac{1}{4}$

$B.$ $\theta \, = \,{60^o}$ $2.$ $\frac{{g{T^2}}}{R} = 8$

$C.$ $\theta \, = \,{30^o}$ $3.$ $\frac{R}{H} = 4\sqrt 3 $

$D.$ $\theta \, = \,{\tan ^{ - 1}}\,4$ $4.$ $\frac{R}{H} = 4$

$K_i :$ initial kinetic energy

$K_h :$ kinetic energy at the highest point

Medium

View Solution

At the top of the trajectory of a projectile, the directions of its velocity and acceleration are

Easy

View Solution

An object is projected with a velocity of $20 m/s$ making an angle of $45^o$ with horizontal. The equation for the trajectory is $h = Ax -Bx^2$ where $h$ is height, $x$ is horizontal distance, $A$ and $B$ are constants. The ratio $A : B$ is ($g = 10 ms^{-2}$)

Difficult

View Solution

Two projectiles are fired from the same point with the same speed at angles of projection $60^o$ and $30^o$ respectively. Which one of the following is true?

Medium

[AIIMS 2014]

View Solution

A ball is projected with a velocity, $10 ms ^{-1}$, at an angle of $60^{\circ}$ with the vertical direction. Its speed at the highest point of its trajectory will be$............... ms ^{-1}$

Medium

[NEET 2022]

View Solution

Column $-I$ Angle of projection	Column $-II$
$A.$ $\theta \, = \,{45^o}$	$1.$ $\frac{{{K_h}}}{{{K_i}}} = \frac{1}{4}$
$B.$ $\theta \, = \,{60^o}$	$2.$ $\frac{{g{T^2}}}{R} = 8$
$C.$ $\theta \, = \,{30^o}$	$3.$ $\frac{R}{H} = 4\sqrt 3 $
$D.$ $\theta \, = \,{\tan ^{ - 1}}\,4$	$4.$ $\frac{R}{H} = 4$

The horizontal range is four times the maximum height attained by a projectile. The angle of projection is .......... $^o$

Similar Questions

At the top of the trajectory of a projectile, the directions of its velocity and acceleration are

An object is projected with a velocity of $20 m/s$ making an angle of $45^o$ with horizontal. The equation for the trajectory is $h = Ax -Bx^2$ where $h$ is height, $x$ is horizontal distance, $A$ and $B$ are constants. The ratio $A : B$ is ($g = 10 ms^{-2}$)

Two projectiles are fired from the same point with the same speed at angles of projection $60^o$ and $30^o$ respectively. Which one of the following is true?

A ball is projected with a velocity, $10 ms ^{-1}$, at an angle of $60^{\circ}$ with the vertical direction. Its speed at the highest point of its trajectory will be$............... ms ^{-1}$