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3-2.Motion in Plane
normal
The horizontal range is four times the maximum height attained by a projectile. The angle of projection is .......... $^o$
A$90$
B$60$
C$45$
D$30$
Solution
$R=4 H$
$\frac{\mathrm{U}^{2} \times 2 \sin \theta \cos \theta}{\mathrm{g}}=4 \times \frac{\mathrm{U}^{2} \sin ^{2} \theta}{2 \mathrm{g}}$
$\tan \theta=1 \quad\left[\theta=45^{\circ}\right]$
$\frac{\mathrm{U}^{2} \times 2 \sin \theta \cos \theta}{\mathrm{g}}=4 \times \frac{\mathrm{U}^{2} \sin ^{2} \theta}{2 \mathrm{g}}$
$\tan \theta=1 \quad\left[\theta=45^{\circ}\right]$
Standard 11
Physics
